60=8w^2+28w

Solution for 60=8w^2+28w equation:

60=8w^2+28w

We move all terms to the left:

60-(8w^2+28w)=0

We get rid of parentheses

-8w^2-28w+60=0

a = -8; b = -28; c = +60;
Δ = b2-4ac
Δ = -282-4·(-8)·60
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-52}{2*-8}=\frac{-24}{-16}
=1+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+52}{2*-8}=\frac{80}{-16}
=-5
$